3.245 \(\int \frac{(A+B \log (\frac{e (a+b x)}{c+d x}))^2}{(f+g x)^2} \, dx\)

Optimal. Leaf size=196 \[ \frac{2 B^2 (b c-a d) \text{PolyLog}\left (2,\frac{(a+b x) (d f-c g)}{(c+d x) (b f-a g)}\right )}{(b f-a g) (d f-c g)}+\frac{2 B (b c-a d) \log \left (1-\frac{(a+b x) (d f-c g)}{(c+d x) (b f-a g)}\right ) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{(b f-a g) (d f-c g)}+\frac{(a+b x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )^2}{(f+g x) (b f-a g)} \]

[Out]

((a + b*x)*(A + B*Log[(e*(a + b*x))/(c + d*x)])^2)/((b*f - a*g)*(f + g*x)) + (2*B*(b*c - a*d)*(A + B*Log[(e*(a
+ b*x))/(c + d*x)])*Log[1 - ((d*f - c*g)*(a + b*x))/((b*f - a*g)*(c + d*x))])/((b*f - a*g)*(d*f - c*g)) + (2*
B^2*(b*c - a*d)*PolyLog[2, ((d*f - c*g)*(a + b*x))/((b*f - a*g)*(c + d*x))])/((b*f - a*g)*(d*f - c*g))

________________________________________________________________________________________

Rubi [B]  time = 1.1194, antiderivative size = 612, normalized size of antiderivative = 3.12, number of steps used = 32, number of rules used = 10, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.345, Rules used = {2525, 12, 2528, 2524, 2418, 2390, 2301, 2394, 2393, 2391} \[ \frac{2 b B^2 \text{PolyLog}\left (2,-\frac{d (a+b x)}{b c-a d}\right )}{g (b f-a g)}+\frac{2 B^2 d \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )}{g (d f-c g)}-\frac{2 B^2 (b c-a d) \text{PolyLog}\left (2,\frac{b (f+g x)}{b f-a g}\right )}{(b f-a g) (d f-c g)}+\frac{2 B^2 (b c-a d) \text{PolyLog}\left (2,\frac{d (f+g x)}{d f-c g}\right )}{(b f-a g) (d f-c g)}+\frac{2 b B \log (a+b x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{g (b f-a g)}-\frac{2 B d \log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{g (d f-c g)}+\frac{2 B (b c-a d) \log (f+g x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{(b f-a g) (d f-c g)}-\frac{\left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )^2}{g (f+g x)}+\frac{2 B^2 d \log (c+d x) \log \left (-\frac{d (a+b x)}{b c-a d}\right )}{g (d f-c g)}+\frac{2 b B^2 \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{g (b f-a g)}-\frac{2 B^2 (b c-a d) \log (f+g x) \log \left (-\frac{g (a+b x)}{b f-a g}\right )}{(b f-a g) (d f-c g)}+\frac{2 B^2 (b c-a d) \log (f+g x) \log \left (-\frac{g (c+d x)}{d f-c g}\right )}{(b f-a g) (d f-c g)}-\frac{b B^2 \log ^2(a+b x)}{g (b f-a g)}-\frac{B^2 d \log ^2(c+d x)}{g (d f-c g)} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*Log[(e*(a + b*x))/(c + d*x)])^2/(f + g*x)^2,x]

[Out]

-((b*B^2*Log[a + b*x]^2)/(g*(b*f - a*g))) + (2*b*B*Log[a + b*x]*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(g*(b*f
- a*g)) - (A + B*Log[(e*(a + b*x))/(c + d*x)])^2/(g*(f + g*x)) + (2*B^2*d*Log[-((d*(a + b*x))/(b*c - a*d))]*Lo
g[c + d*x])/(g*(d*f - c*g)) - (2*B*d*(A + B*Log[(e*(a + b*x))/(c + d*x)])*Log[c + d*x])/(g*(d*f - c*g)) - (B^2
*d*Log[c + d*x]^2)/(g*(d*f - c*g)) + (2*b*B^2*Log[a + b*x]*Log[(b*(c + d*x))/(b*c - a*d)])/(g*(b*f - a*g)) - (
2*B^2*(b*c - a*d)*Log[-((g*(a + b*x))/(b*f - a*g))]*Log[f + g*x])/((b*f - a*g)*(d*f - c*g)) + (2*B*(b*c - a*d)
*(A + B*Log[(e*(a + b*x))/(c + d*x)])*Log[f + g*x])/((b*f - a*g)*(d*f - c*g)) + (2*B^2*(b*c - a*d)*Log[-((g*(c
+ d*x))/(d*f - c*g))]*Log[f + g*x])/((b*f - a*g)*(d*f - c*g)) + (2*b*B^2*PolyLog[2, -((d*(a + b*x))/(b*c - a*
d))])/(g*(b*f - a*g)) + (2*B^2*d*PolyLog[2, (b*(c + d*x))/(b*c - a*d)])/(g*(d*f - c*g)) - (2*B^2*(b*c - a*d)*P
olyLog[2, (b*(f + g*x))/(b*f - a*g)])/((b*f - a*g)*(d*f - c*g)) + (2*B^2*(b*c - a*d)*PolyLog[2, (d*(f + g*x))/
(d*f - c*g)])/((b*f - a*g)*(d*f - c*g))

Rule 2525

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Simp[((d + e*x)^(m
+ 1)*(a + b*Log[c*RFx^p])^n)/(e*(m + 1)), x] - Dist[(b*n*p)/(e*(m + 1)), Int[SimplifyIntegrand[((d + e*x)^(m +
1)*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && RationalFunc
tionQ[RFx, x] && IGtQ[n, 0] && (EqQ[n, 1] || IntegerQ[m]) && NeQ[m, -1]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rule 2524

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[d + e*x]*(a + b
*Log[c*RFx^p])^n)/e, x] - Dist[(b*n*p)/e, Int[(Log[d + e*x]*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x
] /; FreeQ[{a, b, c, d, e, p}, x] && RationalFunctionQ[RFx, x] && IGtQ[n, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rubi steps

\begin{align*} \int \frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{(f+g x)^2} \, dx &=-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{(2 B) \int \frac{(b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(a+b x) (c+d x) (f+g x)} \, dx}{g}\\ &=-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{(2 B (b c-a d)) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{(a+b x) (c+d x) (f+g x)} \, dx}{g}\\ &=-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{(2 B (b c-a d)) \int \left (\frac{b^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(b c-a d) (b f-a g) (a+b x)}+\frac{d^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(b c-a d) (-d f+c g) (c+d x)}+\frac{g^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(b f-a g) (d f-c g) (f+g x)}\right ) \, dx}{g}\\ &=-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{\left (2 b^2 B\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{a+b x} \, dx}{g (b f-a g)}-\frac{\left (2 B d^2\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{c+d x} \, dx}{g (d f-c g)}+\frac{(2 B (b c-a d) g) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{f+g x} \, dx}{(b f-a g) (d f-c g)}\\ &=\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}-\frac{\left (2 b B^2\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (a+b x)}{e (a+b x)} \, dx}{g (b f-a g)}+\frac{\left (2 B^2 d\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{e (a+b x)} \, dx}{g (d f-c g)}-\frac{\left (2 B^2 (b c-a d)\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (f+g x)}{e (a+b x)} \, dx}{(b f-a g) (d f-c g)}\\ &=\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}-\frac{\left (2 b B^2\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (a+b x)}{a+b x} \, dx}{e g (b f-a g)}+\frac{\left (2 B^2 d\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{a+b x} \, dx}{e g (d f-c g)}-\frac{\left (2 B^2 (b c-a d)\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (f+g x)}{a+b x} \, dx}{e (b f-a g) (d f-c g)}\\ &=\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}-\frac{\left (2 b B^2\right ) \int \left (\frac{b e \log (a+b x)}{a+b x}-\frac{d e \log (a+b x)}{c+d x}\right ) \, dx}{e g (b f-a g)}+\frac{\left (2 B^2 d\right ) \int \left (\frac{b e \log (c+d x)}{a+b x}-\frac{d e \log (c+d x)}{c+d x}\right ) \, dx}{e g (d f-c g)}-\frac{\left (2 B^2 (b c-a d)\right ) \int \left (\frac{b e \log (f+g x)}{a+b x}-\frac{d e \log (f+g x)}{c+d x}\right ) \, dx}{e (b f-a g) (d f-c g)}\\ &=\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}-\frac{\left (2 b^2 B^2\right ) \int \frac{\log (a+b x)}{a+b x} \, dx}{g (b f-a g)}+\frac{\left (2 b B^2 d\right ) \int \frac{\log (a+b x)}{c+d x} \, dx}{g (b f-a g)}+\frac{\left (2 b B^2 d\right ) \int \frac{\log (c+d x)}{a+b x} \, dx}{g (d f-c g)}-\frac{\left (2 B^2 d^2\right ) \int \frac{\log (c+d x)}{c+d x} \, dx}{g (d f-c g)}-\frac{\left (2 b B^2 (b c-a d)\right ) \int \frac{\log (f+g x)}{a+b x} \, dx}{(b f-a g) (d f-c g)}+\frac{\left (2 B^2 d (b c-a d)\right ) \int \frac{\log (f+g x)}{c+d x} \, dx}{(b f-a g) (d f-c g)}\\ &=\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{2 B^2 d \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{g (d f-c g)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}+\frac{2 b B^2 \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{g (b f-a g)}-\frac{2 B^2 (b c-a d) \log \left (-\frac{g (a+b x)}{b f-a g}\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 B^2 (b c-a d) \log \left (-\frac{g (c+d x)}{d f-c g}\right ) \log (f+g x)}{(b f-a g) (d f-c g)}-\frac{\left (2 b B^2\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,a+b x\right )}{g (b f-a g)}-\frac{\left (2 b^2 B^2\right ) \int \frac{\log \left (\frac{b (c+d x)}{b c-a d}\right )}{a+b x} \, dx}{g (b f-a g)}-\frac{\left (2 B^2 d\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,c+d x\right )}{g (d f-c g)}-\frac{\left (2 B^2 d^2\right ) \int \frac{\log \left (\frac{d (a+b x)}{-b c+a d}\right )}{c+d x} \, dx}{g (d f-c g)}+\frac{\left (2 B^2 (b c-a d) g\right ) \int \frac{\log \left (\frac{g (a+b x)}{-b f+a g}\right )}{f+g x} \, dx}{(b f-a g) (d f-c g)}-\frac{\left (2 B^2 (b c-a d) g\right ) \int \frac{\log \left (\frac{g (c+d x)}{-d f+c g}\right )}{f+g x} \, dx}{(b f-a g) (d f-c g)}\\ &=-\frac{b B^2 \log ^2(a+b x)}{g (b f-a g)}+\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{2 B^2 d \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{g (d f-c g)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}-\frac{B^2 d \log ^2(c+d x)}{g (d f-c g)}+\frac{2 b B^2 \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{g (b f-a g)}-\frac{2 B^2 (b c-a d) \log \left (-\frac{g (a+b x)}{b f-a g}\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 B^2 (b c-a d) \log \left (-\frac{g (c+d x)}{d f-c g}\right ) \log (f+g x)}{(b f-a g) (d f-c g)}-\frac{\left (2 b B^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{d x}{b c-a d}\right )}{x} \, dx,x,a+b x\right )}{g (b f-a g)}-\frac{\left (2 B^2 d\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-b c+a d}\right )}{x} \, dx,x,c+d x\right )}{g (d f-c g)}+\frac{\left (2 B^2 (b c-a d)\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-b f+a g}\right )}{x} \, dx,x,f+g x\right )}{(b f-a g) (d f-c g)}-\frac{\left (2 B^2 (b c-a d)\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{d x}{-d f+c g}\right )}{x} \, dx,x,f+g x\right )}{(b f-a g) (d f-c g)}\\ &=-\frac{b B^2 \log ^2(a+b x)}{g (b f-a g)}+\frac{2 b B \log (a+b x) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{g (b f-a g)}-\frac{\left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )^2}{g (f+g x)}+\frac{2 B^2 d \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{g (d f-c g)}-\frac{2 B d \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{g (d f-c g)}-\frac{B^2 d \log ^2(c+d x)}{g (d f-c g)}+\frac{2 b B^2 \log (a+b x) \log \left (\frac{b (c+d x)}{b c-a d}\right )}{g (b f-a g)}-\frac{2 B^2 (b c-a d) \log \left (-\frac{g (a+b x)}{b f-a g}\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 B (b c-a d) \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 B^2 (b c-a d) \log \left (-\frac{g (c+d x)}{d f-c g}\right ) \log (f+g x)}{(b f-a g) (d f-c g)}+\frac{2 b B^2 \text{Li}_2\left (-\frac{d (a+b x)}{b c-a d}\right )}{g (b f-a g)}+\frac{2 B^2 d \text{Li}_2\left (\frac{b (c+d x)}{b c-a d}\right )}{g (d f-c g)}-\frac{2 B^2 (b c-a d) \text{Li}_2\left (\frac{b (f+g x)}{b f-a g}\right )}{(b f-a g) (d f-c g)}+\frac{2 B^2 (b c-a d) \text{Li}_2\left (\frac{d (f+g x)}{d f-c g}\right )}{(b f-a g) (d f-c g)}\\ \end{align*}

Mathematica [B]  time = 0.958893, size = 402, normalized size = 2.05 \[ \frac{\frac{B \left (-b B (d f-c g) \left (\log (a+b x) \left (\log (a+b x)-2 \log \left (\frac{b (c+d x)}{b c-a d}\right )\right )-2 \text{PolyLog}\left (2,\frac{d (a+b x)}{a d-b c}\right )\right )+B d (b f-a g) \left (2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )+\log (c+d x) \left (2 \log \left (\frac{d (a+b x)}{a d-b c}\right )-\log (c+d x)\right )\right )-2 B g (b c-a d) \left (\text{PolyLog}\left (2,\frac{b (f+g x)}{b f-a g}\right )-\text{PolyLog}\left (2,\frac{d (f+g x)}{d f-c g}\right )+\log (f+g x) \left (\log \left (\frac{g (a+b x)}{a g-b f}\right )-\log \left (\frac{g (c+d x)}{c g-d f}\right )\right )\right )+2 b \log (a+b x) (d f-c g) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )-2 d (b f-a g) \log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )+2 g (b c-a d) \log (f+g x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )\right )}{(b f-a g) (d f-c g)}-\frac{\left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )^2}{f+g x}}{g} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*Log[(e*(a + b*x))/(c + d*x)])^2/(f + g*x)^2,x]

[Out]

(-((A + B*Log[(e*(a + b*x))/(c + d*x)])^2/(f + g*x)) + (B*(2*b*(d*f - c*g)*Log[a + b*x]*(A + B*Log[(e*(a + b*x
))/(c + d*x)]) - 2*d*(b*f - a*g)*(A + B*Log[(e*(a + b*x))/(c + d*x)])*Log[c + d*x] + 2*(b*c - a*d)*g*(A + B*Lo
g[(e*(a + b*x))/(c + d*x)])*Log[f + g*x] - b*B*(d*f - c*g)*(Log[a + b*x]*(Log[a + b*x] - 2*Log[(b*(c + d*x))/(
b*c - a*d)]) - 2*PolyLog[2, (d*(a + b*x))/(-(b*c) + a*d)]) + B*d*(b*f - a*g)*((2*Log[(d*(a + b*x))/(-(b*c) + a
*d)] - Log[c + d*x])*Log[c + d*x] + 2*PolyLog[2, (b*(c + d*x))/(b*c - a*d)]) - 2*B*(b*c - a*d)*g*((Log[(g*(a +
b*x))/(-(b*f) + a*g)] - Log[(g*(c + d*x))/(-(d*f) + c*g)])*Log[f + g*x] + PolyLog[2, (b*(f + g*x))/(b*f - a*g
)] - PolyLog[2, (d*(f + g*x))/(d*f - c*g)])))/((b*f - a*g)*(d*f - c*g)))/g

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Maple [F]  time = 2.067, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{ \left ( gx+f \right ) ^{2}} \left ( A+B\ln \left ({\frac{e \left ( bx+a \right ) }{dx+c}} \right ) \right ) ^{2}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A+B*ln(e*(b*x+a)/(d*x+c)))^2/(g*x+f)^2,x)

[Out]

int((A+B*ln(e*(b*x+a)/(d*x+c)))^2/(g*x+f)^2,x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} 2 \, A B{\left (\frac{b \log \left (b x + a\right )}{b f g - a g^{2}} - \frac{d \log \left (d x + c\right )}{d f g - c g^{2}} + \frac{{\left (b c - a d\right )} \log \left (g x + f\right )}{b d f^{2} + a c g^{2} -{\left (b c + a d\right )} f g} - \frac{\log \left (\frac{b e x}{d x + c} + \frac{a e}{d x + c}\right )}{g^{2} x + f g}\right )} - B^{2}{\left (\frac{\log \left (d x + c\right )^{2}}{g^{2} x + f g} + \int -\frac{d g x \log \left (e\right )^{2} + c g \log \left (e\right )^{2} +{\left (d g x + c g\right )} \log \left (b x + a\right )^{2} + 2 \,{\left (d g x \log \left (e\right ) + c g \log \left (e\right )\right )} \log \left (b x + a\right ) - 2 \,{\left ({\left (g \log \left (e\right ) - g\right )} d x + c g \log \left (e\right ) - d f +{\left (d g x + c g\right )} \log \left (b x + a\right )\right )} \log \left (d x + c\right )}{d g^{3} x^{3} + c f^{2} g +{\left (2 \, d f g^{2} + c g^{3}\right )} x^{2} +{\left (d f^{2} g + 2 \, c f g^{2}\right )} x}\,{d x}\right )} - \frac{A^{2}}{g^{2} x + f g} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*(b*x+a)/(d*x+c)))^2/(g*x+f)^2,x, algorithm="maxima")

[Out]

2*A*B*(b*log(b*x + a)/(b*f*g - a*g^2) - d*log(d*x + c)/(d*f*g - c*g^2) + (b*c - a*d)*log(g*x + f)/(b*d*f^2 + a
*c*g^2 - (b*c + a*d)*f*g) - log(b*e*x/(d*x + c) + a*e/(d*x + c))/(g^2*x + f*g)) - B^2*(log(d*x + c)^2/(g^2*x +
f*g) + integrate(-(d*g*x*log(e)^2 + c*g*log(e)^2 + (d*g*x + c*g)*log(b*x + a)^2 + 2*(d*g*x*log(e) + c*g*log(e
))*log(b*x + a) - 2*((g*log(e) - g)*d*x + c*g*log(e) - d*f + (d*g*x + c*g)*log(b*x + a))*log(d*x + c))/(d*g^3*
x^3 + c*f^2*g + (2*d*f*g^2 + c*g^3)*x^2 + (d*f^2*g + 2*c*f*g^2)*x), x)) - A^2/(g^2*x + f*g)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{B^{2} \log \left (\frac{b e x + a e}{d x + c}\right )^{2} + 2 \, A B \log \left (\frac{b e x + a e}{d x + c}\right ) + A^{2}}{g^{2} x^{2} + 2 \, f g x + f^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*(b*x+a)/(d*x+c)))^2/(g*x+f)^2,x, algorithm="fricas")

[Out]

integral((B^2*log((b*e*x + a*e)/(d*x + c))^2 + 2*A*B*log((b*e*x + a*e)/(d*x + c)) + A^2)/(g^2*x^2 + 2*f*g*x +
f^2), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*ln(e*(b*x+a)/(d*x+c)))**2/(g*x+f)**2,x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \log \left (\frac{{\left (b x + a\right )} e}{d x + c}\right ) + A\right )}^{2}}{{\left (g x + f\right )}^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((A+B*log(e*(b*x+a)/(d*x+c)))^2/(g*x+f)^2,x, algorithm="giac")

[Out]

integrate((B*log((b*x + a)*e/(d*x + c)) + A)^2/(g*x + f)^2, x)